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Q: How can you get five using only four 4s?

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44 divided by .44

how do i make 17 using only 2 4 6 8

if you want to make eleven using only four 4s, this is the answer 4/.4+4/4(=10 + 1= 11) TA DA !

(44 - 4)/4

yrs

44-4/4

(4 * 4) - (4/4) equals 15.

4/4 + 4/4

4+4-(4/4)

Google "Four Fours" and you will find a number of solutions, presented more comprehensively than we can.

One possible way: Make a 10 using five 4s as follows: 4 + 4 + (4 + 4)/4 = 10 Make another two 10s using five 4s in each. Multiply these three 10s.

4 ×(4 − 4 ÷ 4) or (44 + 4) ÷ 4

4+4+(4-4) = 4

The answer is 4! - [(4+4)/4]

4 + 4 + 4/4 = 9

((4*4)-4)/+4 = 3

4+4+4x4 by the power of 0.

4!+(4+4!)/4

You can get 9 with the sum 4 + 4 + (4/4) = 9

44/4 + √4 = 11 + 2 = 13

The answer is 9C4 = 9*8*7*6/(4*3*2*1) = 126 ways.

If your playing 4 4s, 4! x 4 + root4 + root 4

It is: 4s = 64

There is not enough information in the question to answer the question. It depends on what happens in the ellipsis. If the number of fours keeps increasing forever then it is not a rational number, but if it settles at three 4s, or goes one 4, two 4s, three 4s (and maybe four 4s, five 4s) and then back to one 4 then it is.

4/.4 + 4/4 [= 10+1 = 11]